Advanced Organic Chemistry: Mass spectrum of 2-chloro-2-methylpropane (CH3)3CCl

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Interpreting the mass spectrum of 2-chloro-2-methylpropane

[Author ©  Dr Phil Brown PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK A level chemistry courses & US K12 grade 11, grade 12 and AP honors chemistry courses: Molecular spectrometry - analysing the mass spectrum of 2-chloro-2-methylpropane [updated Mar 12th 2026 *]

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 Links associated with 2-chloro-2-methylpropane

 The chemistry of organic halogen compounds

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 Mass spectrometry - introduction and spectra index

See also Comparing infrared, mass, 1H NMR & 13C NMR spectra of the 4 structural isomers of C4H9Cl


Introductory note on the mass spectrum of 2-chloro-2-methylpropane

Students and teachers please note my explanation of the mass spectrum of 2-chloro-2-methylpropane is designed for advanced, but pre-university, chemistry courses.

If M represents the 2-chloro-2-methylpropane molecule, the initial ionisation to give the molecular ion is:

M(g) + high KE e-  ==> [M]+(g) + 2e- and for fragmentation equations assume [M]+ is the start of the processes and all species are in a gaseous state.

I've not usually shown an unpaired electron on e.g. an ion or a non-ionised alkyl radical R e.g.

[M]+ ==> [X]+  +  R, but you should be aware this is a more accurate depiction of some processes.

I've used simplified equations to show how some of the ions that might be formed in the fragmentation pattern for the mass spectrum of 2-chloro-2-methylpropane and only the formation of singly charged positive are considered for the mass spectrum of 2-chloro-2-methylpropane.

I've included a stick diagram and table of m/z ions for the mass spectrum of 2-chloro-2-methylpropane and doing the mass spectrum analysis under standard conditions, databases can be compiled based on complex fingerprint patterns, often involving the relative intensities of many fragment ions, and used to identify compounds including 2-chloro-2-methylpropane.

In selected cases, where two different fragment ions have the same integer m/z value, I've pointed out that modern mass spectrometers can measure relative ion mass to four decimal places. So, using accurate isotopic masses, I've calculated the accurate ion masses, BUT strictly speaking, 0.0005 should be deducted for singly charged ions to account for the loss of the electron in their formation. I have NOT done this, but the mass spectrometer software does!

C4H9Cl (CH3)3CCl mass spectrum of 2-chloro-2-methylpropane fragmentation pattern of m/z m/e ions for analysis and identification of  tert-butyl chloride image diagram doc brown's advanced organic chemistry revision notes 

(c) doc b, (c) doc b, (c) doc b, (c) doc b, 2-chloro-2-methylpropane

For more see Molecular structure, classification and naming of halogenoalkanes (haloalkanes)

Interpreting the fragmentation pattern of the mass spectrum of 2-chloro-2-methylpropane

[M]+ is the molecular ion peak (M) with an m/z of 92 corresponding to [C4H9Cl]+, the original 2-chloro-2-methylpropane molecule minus an electron, [(CH3)3C35Cl]+. Since this ion is so unstable, there is even less chance of observing the m/z 94 M+2 ion [(CH3)3C37Cl]+ (see note below on isotopes).

Not here, but at a lower electron beam energy, you might see a tiny peak at m/z 94 (M+2) corresponding to another molecular ion containing the heavier isotope of chlorine, [(CH3)3C37Cl]+.

Since chlorine has two common isotopes of 35Cl and 37Cl in the approximate ratio of 3 : 1, you should observe double peaks in the intensity ratio 3 : 1, two mass units apart for molecular fragments containing a chlorine atom from the fragmentation of 1-chlorobutane.

An example of this are quoted in the table below for m/z values of 79 and 77, you can see they are roughly in the ratio 3 : 1 in the mass spectrum diagram above.

You 'might' see another very tiny M+1 peak at m/z 93, corresponds to an ionised 2-chloro-2-methylpropane molecule with one 13C atom in it i.e. an ionised 2-chloro-2-methylpropane molecule of formula [13C12C3H935Cl]+

Carbon-13 only accounts for ~1% of all carbon atoms (12C ~99%), but the more carbon atoms in the molecule, the greater the probability of observing this 13C M+1 peak.

2-chloro-2-methylpropane has 4 carbon atoms, so on average, ~1 in 25 molecules will contain a 13C atom.

The most abundant ion of the molecule under mass spectrometry investigation (2-chloro-2-methylpropane) is usually given an arbitrary abundance value of 100, called the base ion peak, and all other abundances ('intensities') are measured against it.

The base peak ion for the mass spectrum of 2-chloro-2-methylpropane is the m/z 57 ion [C4H9]+

Identifying the species giving the most prominent peaks (apart from M) in the fragmentation pattern of 2-chloro-2-methylpropane.

Unless otherwise indicated, assume the carbon atoms in 2-chloro-2-methylpropane are the 12C isotope.

Some of the possible positive ions, [molecular fragment]+, formed in the mass spectrometry of 2-chloro-2-methylpropane.

m/z value of [fragment]+ 79 77 57  [C4H9]+ 56 55
[molecular fragment]+ [(CH3)2C37Cl]+ [(CH3)2C35Cl]+ [(CH3)3C]+ [C4H8]+ [C4H7]+
m/z value of [fragment]+ 42 41 39 29 28 27 15
[molecular fragment]+ [C3H6]+ [C3H5]+ [C3H3]+ [C2H5]+ [C2H4]+ [C2H3]+ [CH3]+

Analysing and explaining the principal ions in the fragmentation pattern of the mass spectrum of 2-chloro-2-methylpropane

PLEASE NOTE I have found it difficult to find 'authentic' equations to explain mass spectra fragmentation patterns and it is complex chemistry! I've identified the formulae of the ionised fragments on the mass spectrum diagram, but the equations are from the internet or my conjecture as to how the ions might be formed - please take care in using the information, especially for assignments at university or pre-university level.

Atomic masses: H = 1; C = 12; Cl = 35 or 37 (3:1)

Bond enthalpies kJ/mol: C-C = 348;  C-Cl = 338; C-H = 412

Possible equations to explain some of the most abundant ion peaks in the mass spectrum of 2-chloro-2-methylpropane

Note the molecular ion peaks (M and M+2) are very small indicating the parent molecular ion of 2-chloro-2-methylpropane fragments very easily.

Formation of m/z 77 and 79 ions:

[(CH3)3C35Cl]+  ===>  [(CH3)2C35Cl]+  or  [(CH3)2C37Cl]+  +  CH3

Scission of the C-C bond to lose a methyl group, mass loss 92 - 15 = 77, 94 - 15 = 79.

Low probability due to strength of C-C bond, scission of the weaker C-Cl bond much more likely.

Where R is alkyl, the double RCl m/z ion peaks of roughly 3 : 1 abundance ratio are characteristic of organo-chlorine compounds i.e. caused by the 3 : 1 isotope ratio of 35Cl : 37Cl.

Formation of m/z 57 ion:

[(CH3)3CCl]+  ===>  [(CH3)3C]+  +  Cl

Formed by the scission of the C-Cl bond, the weakest bond in the 2-chloro-2-methylpropane molecule, loss of chlorine radical.

The m/z 57 ion is the base peak ion, the most abundant and 'stable' ion fragment.

The m/z 57 ion is a tertiary carbocation, the most stable type of alkyl based ion, the positive charge is stabilised by the +I (inductive) effect of the three methyl groups.

Another reason why the ionised fragments, not containing chlorine, are more likely to be formed, is the more electronegative chlorine tends to make the chlorine containing fragment retain the electrons.

Note the m/z peak of 58 could also correspond with the ion [13C12C3H9]+.

Formation of m/z 56 ion

[(CH3)3CCl]+  ===>  [C4H8]+  +  HCl

Elimination of HCl from the parent molecular ion.

Formation of m/z 41 ion:

[?]+  ===>  [C3H5]+  +  ?

Formation of m/z 39 ion:

[C3H5]+  ===>  [C3H3]+  +  H2

Formation of m/z 29 ion:

[?]+  ===>  [C2H5]+  +  ?

Formation of m/z 27 ion:

[C2H5]+  ===>  [C2H3]+  +  H2

Formation of m/z 15 ion:

[(CH3)3CCl]+  ===>  [CH3]+  +  (CH3)2CCl

C-C bond scission of the parent molecular ion (or other fragment) to free a positively charged methyl group


(c) doc bSummary of the mass spectrum of 2-chloro-2-methylpropane and extra comments

The mass spectrum of 2-chloro-2-methylpropane (tert-butyl chloride) with exam precision and structural insight.


Key Fragment Ions in mass spectrum of 2-chloro-2-methylpropane

m/z Ion Formula Origin / Fragmentation Pathway Notes
92 C4H9Cl⁺ Molecular ion (M⁺) Often weak due to fragmentation tendency
77 & 79 C3H6Cl⁺ Loss of methyl group from parent molecular ion C-C bond fission less likely than C-Cl fission to give m/z 57 ion
57 C4H9 Loss of Cl• radical (M⁺ – 35) Base ion peak (most intense)
41 C3H5 Further fragmentation of C3H7 or C4H9 Common alkyl fragment
39 C3H3 Common in alkane spectra, from later fragmentation stage Seen in many branched alkanes
35 & 37 Cl⁺ isotopes Chlorine isotopic peaks (³⁵Cl and ³⁷Cl) 3:1 ratio confirms presence of chlorine

Common Misconceptions about the mass spectrum of 2-chloro-2-methylpropane (see also below)

  • Confusing base peak with molecular ion: Students often assume the tallest peak is the molecular ion. Clarify that the base peak (m/z 57) is a fragment, not M⁺.
  • Ignoring isotope patterns: Overlooking the 3:1 ratio of Cl⁺ peaks can lead to missed identification of halogen presence.
  • Expecting oxygen-containing fragments: Some learners mistakenly look for m/z 45 or 60, typical of alcohols or esters—irrelevant here.

Exam Tips for questions involving the mass spectrum of 2-chloro-2-methylpropane (see also above)

  • Use isotope clues: The presence of m/z 35 and 37 in a 3:1 ratio is a strong indicator of chlorine—use this to eliminate non-halogen options.
  • Compare with t-butanol: t-butanol shows a molecular ion at m/z 74 and lacks Cl isotope peaks—great for contrast questions.
  • Watch for base peak logic: The base peak at m/z 57 corresponds to the stable tert-butyl cation, a common fragment in branched alkanes.
  • Check fragmentation logic: Emphasize that loss of Cl• (not Cl⁻) leads to m/z 57—this helps in mechanism-based questions.

(c) doc bPractice questions based on the mass spectrum of 2-chlor

Two technically robust multiple-choice questions on the mass spectrum of 2-chloro-2-methylpropane (C4H9Cl), designed for advanced pre-university chemistry students across AQA, Edexcel, OCR, WJEC, CCEA, CIE, IB, and US AP/Honors curricula.

Each question includes a model answer and distractor analysis to support deeper understanding and exam readiness.

ANSWERS


Question 1: Molecular Ion Peak Identification in the mass spectrum of 2-chloro-2-methylpropane

Which of the following m/z values corresponds to the molecular ion peak (M⁺) of 2-chloro-2-methylpropane in its mass spectrum, assuming the presence of the most abundant chlorine isotope?

  1. 92
  2. 90
  3. 91
  4. 94

Question 2: Fragmentation Pattern Recognition in the mass spectrum of 2-chloro-2-methylpropane

In the mass spectrum of 2-chloro-2-methylpropane, a prominent fragment ion appears at m/z 57. Which fragment is most likely responsible for this peak?

  1. CH3CH2CH2
  2. (CH3)3C⁺
  3. CH3CHCl⁺
  4. CH3CH2Cl⁺

Question 3: Isotopic Pattern Interpretation on the mass spectrum of 2-chloro-2-methylpropane

The molecular ion region of the mass spectrum of 2-chloro-2-methylpropane shows two peaks at m/z 92 and 94 in a 3:1 ratio.

What does this pattern indicate about the structure of the molecule?

  1. The molecule contains one chlorine atom, which exists as two isotopes in a 3:1 ratio.
  2. The molecule contains two chlorine atoms, each contributing to the isotopic pattern.
  3. The molecule contains one bromine atom, which has two isotopes in a 3:1 ratio.
  4. The molecule contains both chlorine and bromine atoms, producing a complex isotopic pattern.

Question 4: Fragmentation Pathway and Stability of the mass spectrum of 2-chloro-2-methylpropane

Which of the following best explains why the base peak in the mass spectrum of 2-chloro-2-methylpropane appears at m/z 57?

  1. It corresponds to the loss of a methyl radical from the molecular ion.
  2. It is the most stable carbocation formed after cleavage of the C–Cl bond.
  3. It results from the rearrangement of the molecular ion to form a neutral alkene.
  4. It is the molecular ion peak, as the molecule is resistant to fragmentation.
Comparing the infrared, mass, 1H NMR and 13C NMR spectra of the 4 halogenoalkane isomers of C4H9Cl

NOTE: The images are linked to their original detailed spectral analysis pages AND can be doubled in size with touch screens to increase the definition to the original 1-chlorobutane, 2-chlorobutane, 1-chloro-2-methylpropane and 2-chloro-2-methylpropane image sizes.  These four molecules are structural isomers of molecular formula C4H9Cl and exemplify the infrared, mass, 1H NMR and 13C NMR spectra of lower aliphatic halogenoalkanes (haloalkanes, alkyl halides, chloroalkanes, alkyl chlorides).

INFRARED SPECTRA (above): Apart from the significant differences in the fingerprint region at wavenumbers 1500 to 400 cm-1, there are no other great striking differences, but each could be identified from its infrared spectrum. The infrared spectrum of 2-chloro-2-methylpropane is noticeably simpler in the fingerprint region, perhaps due to the greater symmetry of the molecule.

MASS SPECTRA (above): Theoretically, all four can give the parent molecular ions of m/z 92 and 94, but they are all relatively tiny peaks. 2-chlorobutane and 2-chloro-2-methylpropane give a base ion peak of m/z 57. The base ion peak for 1-chlorobutane is m/z 56 and that of 1-chloro-2-methylpropane is m/z 43. Each gives different patterns of pairs of m/z values two mass units apart, in the peak height ratio of 3:1, if the positive fragment contains a chlorine atom (35Cl or 37Cl) e.g look for m/z pairs 49/51, 63/65 and 77/79 in their mass spectra.

1H NMR SPECTRA (above): The 1H NMR spectra of all four molecules give different integrated proton ratios i.e.1-chlorobutane four peaks of ratio 3:2:2:2; 2-chlorobutane four peaks of ratio 3:3:2:1, 1-chloro-2-methylpropane three peaks of ratio 6:2:1 and 2-chloro-2-methylpropane gives just one peak '1' (effectively no ratio involved), so all four molecular structures can be distinguished from each other by their 1H NMR spectra proton ratios, numbers of peaks and (n+1) rule splitting patterns.

13C NMR SPECTRA (above): The 13C NMR spectra of the four molecules show various numbers of carbon-13 chemical environments i.e 1-chlorobutane and 2-chlorobutane show four 13C NMR resonances, 1-chloro-2-methylpropane three 13C NMR resonances and 2-chloro-2-methylpropane only two 13C resonances (3 and 2 chemical environments respectively. Therefore 1-chloro-2-methylpropane and 2-chloro-2-methylpropane can be distinguished from the other three by their number of resonances in their 13C NMR spectra, but 1-chlorobutane and 2-chlorobutane cannot be distinguished from each other from their number of 13C NMR resonance lines - other data would be required.

Key words & phrases: C4H9Cl (CH3)3CCl image diagram on how to interpret and explain the mass spectrum of 2-chloro-2-methylpropane m/z m/e base peaks, image and diagram of the mass spectrum of 2-chloro-2-methylpropane, details of the mass spectroscopy of 2-chloro-2-methylpropane,  low and high resolution mass spectrum of 2-chloro-2-methylpropane, prominent m/z peaks in the mass spectrum of 2-chloro-2-methylpropane, comparative mass spectra of 2-chloro-2-methylpropane, the molecular ion peak in the mass spectrum of 2-chloro-2-methylpropane, analysing and understanding the fragmentation pattern of the mass spectrum of 2-chloro-2-methylpropane, characteristic pattern of peaks in the mass spectrum of 2-chloro-2-methylpropane, relative abundance of mass ion peaks in the mass spectrum of 2-chloro-2-methylpropane, revising the mass spectrum of 2-chloro-2-methylpropane, revision of mass spectroscopy of 2-chloro-2-methylpropane, most abundant ions in the mass spectrum of 2-chloro-2-methylpropane, how to construct the mass spectrum diagram for abundance of fragmentation ions in the mass spectrum of 2-chloro-2-methylpropane, how to analyse the mass spectrum of 2-chloro-2-methylpropane, how to describe explain the formation of fragmented ions in the mass spectra of 2-chloro-2-methylpropane equations for explaining the formation of the positive ions in the fragmentation of the ionised molecule of 2-chloro-2-methylpropane recognising the base ion peak of 2-chloro-2-methylpropane interpreting interpretation the mass spectrum of 2-chloro-2-methylpropane  tert-butyl chloride Stick diagram of the relative abundance of ionised fragments in the fingerprint pattern of the mass spectrum of 2-chloro-2-methylpropane. Table of the m/e m/z values and formula of the ionised fragments in the mass spectrum of 2-chloro-2-methylpropane. The m/e m/z value of the molecular ion peak in the mass spectrum of 2-chloro-2-methylpropane.  The m/e m/z value of the base ion peak in the mass spectrum of 2-chloro-2-methylpropane. Possible examples of equations showing the formation of the ionised fragments in 2-chloro-2-methylpropane. Revision notes on the mass spectrum of 2-chloro-2-methylpropane. Matching and deducing the structure of the 2-chloro-2-methylpropane molecule from its mass spectrum. Mass spectroscopy of  aliphatic halogenoalkanes haloalkanes alkyl halides alkyl chlorides chloroalkanes, mass spectra of 2-chloro-2-methylpropane, an isomer of molecular formula C4H9Cl How do you interpret the mass spectrum of 2-chloro-2-methylpropane How to interpret the mass spectrum of 2-chloro-2-methylpropane Explanatory diagram of the mass spectrum of the 2-chloro-2-methylpropane molecule in terms of its molecular structure. Listing data of the prominent main peaks in the mass spectrum of 2-chloro-2-methylpropane. How to explain the mass spectrum of 2-chloro-2-methylpropane. The m/z value of the molecular ion peak in the mass spectrum of 2-chloro-2-methylpropane. Identifying 2-chloro-2-methylpropane from its mass spectrum pattern. The m/z m/e peak analysis of the mass spectrum of the 2-chloro-2-methylpropane molecule. The uses of the mass spectrum of the 2-chloro-2-methylpropane molecule.  The distinctive features of the mass spectrum of the 2-chloro-2-methylpropane molecule explained. explaining the fragmentation pattern of the mass spectrum of 2-chloro-2-methylpropane equations showing the formation of the ionised fragments in the mass spectrum of 2-chloro-2-methylpropane  what does the mass spectrum tell you about the structure and properties of the 2-chloro-2-methylpropane molecule? Data table of ionised fragments in the mass spectrum of 2-chloro-2-methylpropane and equations for their formation in the fragmentation of 2-chloro-2-methylpropane molecules


ANSWERS to the mass spectrum questions

Question 1: Molecular Ion Peak Identification in the mass spectrum of 2-chloro-2-methylpropane

Which of the following m/z values corresponds to the molecular ion peak (M⁺) of 2-chloro-2-methylpropane in its mass spectrum, assuming the presence of the most abundant chlorine isotope?

  1. 92
  2. 90
  3. 91
  4. 94

Correct Answer: A

Explanation:

  • Molecular formula: C4H9Cl
  • Atomic masses:
    • C = 12 × 4 = 48
    • H = 1 × 9 = 9
    • Cl = ³⁵Cl = 35
      → Total = 48 + 9 + 35 =
      92

This corresponds to the M⁺ peak with ³⁵Cl.

A second peak at m/z 94 (from ³⁷Cl) also appears, typically in a 3:1 ratio due to chlorine isotope abundance.

Distractor Analysis:

Option Why It’s Incorrect
B (90) Too low; omits part of the molecular mass.
C (91) Not a valid isotope combination.
D (94) Represents the M⁺ peak with ³⁷Cl, not the most abundant isotope.

Question 2: Fragmentation Pattern Recognition in the mass spectrum of 2-chloro-2-methylpropane

In the mass spectrum of 2-chloro-2-methylpropane, a prominent fragment ion appears at m/z 57. Which fragment is most likely responsible for this peak?

  1. CH3CH2CH2
  2. (CH3)3C⁺
  3. CH3CHCl⁺
  4. CH3CH2Cl⁺

Correct Answer: B

Explanation:

  • The molecule fragments by losing the chlorine atom (Cl•), forming the tert-butyl cation: (CH₃)₃C⁺
  • Mass:
    • C = 12 × 4 = 48
    • H = 1 × 9 = 9
      → Total =
      57

This is a highly stable carbocation due to tertiary carbon center and resonance stabilization.

Distractor Analysis:

Option Why It’s Incorrect
A CH3CH2CH2⁺ = 43; too low and not formed from this structure.
C CH3CHCl⁺ = 64; not a major fragment from this molecule.
D CH3CH2Cl⁺ = 78; too high and not consistent with the structure.

Question 3: Isotopic Pattern Interpretation on the mass spectrum of 2-chloro-2-methylpropane

The molecular ion region of the mass spectrum of 2-chloro-2-methylpropane shows two peaks at m/z 92 and 94 in a 3:1 ratio.

What does this pattern indicate about the structure of the molecule?

  1. The molecule contains one chlorine atom, which exists as two isotopes in a 3:1 ratio.
  2. The molecule contains two chlorine atoms, each contributing to the isotopic pattern.
  3. The molecule contains one bromine atom, which has two isotopes in a 3:1 ratio.
  4. The molecule contains both chlorine and bromine atoms, producing a complex isotopic pattern.

Correct Answer: A

Explanation:

  • Chlorine has two naturally occurring isotopes:
    • ³⁵Cl (≈75%)
    • ³⁷Cl (≈25%)
  • A molecule with one chlorine atom will show a molecular ion (M⁺) peak and an M+2 peak in a 3:1 ratio.
  • 2-chloro-2-methylpropane contains only one Cl atom, so the observed pattern at m/z 92 (³⁵Cl) and m/z 94 (³⁷Cl) confirms this.

Distractor Analysis:

Option Why It’s Incorrect
B Two Cl atoms would give a 9:6:1 triplet pattern (binomial distribution), not 3:1.
C Bromine has a 1:1 isotope ratio (⁷⁹Br and ⁸¹Br), not 3:1.
D The spectrum lacks the 1:2:1 or 1:1:1:1 patterns expected from multiple halogens.

Question 4: Fragmentation Pathway and Stability of the mass spectrum of 2-chloro-2-methylpropane

Which of the following best explains why the base peak in the mass spectrum of 2-chloro-2-methylpropane appears at m/z 57?

  1. It corresponds to the loss of a methyl radical from the molecular ion.
  2. It is the most stable carbocation formed after cleavage of the C–Cl bond.
  3. It results from the rearrangement of the molecular ion to form a neutral alkene.
  4. It is the molecular ion peak, as the molecule is resistant to fragmentation.

Correct Answer: B

Explanation:

  • The base peak is the most intense peak, representing the most stable and abundant fragment.
  • In 2-chloro-2-methylpropane, cleavage of the C–Cl bond forms a tertiary carbocation: (CH3)3C⁺
  • This ion has m/z 57 and is highly stable due to hyperconjugation and inductive effects from the three methyl groups.

Distractor Analysis:

Option Why It’s Incorrect
A Loss of a methyl radical would give m/z 77, not 57.
C Rearrangement to a neutral alkene would not produce a positively charged ion at m/z 57.
D The molecular ion is at m/z 92/94; m/z 57 is a fragment, not the parent ion.

Links associated with 2-chloro-2-methylpropane

The chemistry of HALOGENOALKANES (haloalkanes) revision notes INDEX

The infrared spectrum of 2-chloro-2-methylpropane (tert-butyl chloride)

The H-1 NMR spectrum of 2-chloro-2-methylpropane (tert-butyl chloride)

The C-13 NMR spectrum of 2-chloro-2-methylpropane (tert-butyl chloride)

 Mass spectrometry - introduction and spectra index

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Website content © Dr Phil Brown 2000+. All copyrights reserved on revision notes, images, quizzes, worksheets etc. Copying of Doc Brown's pre-university advanced level chemistry website material is NOT permitted. Exam revision summaries & references to chemistry course specifications are unofficial. These organic chemistry revision notes on the spectroscopy of 2-chloro-2-methylpropane - its mass spectrum are suitable for use of pre-university students studying AQA advanced level chemistry, Edexcel advanced level chemistry, OCR advanced level chemistry, IB advanced level chemistry, WJEC (Eduqas) advanced level chemistry, CIE Cambridge advanced level chemistry, US grade 11-12 AP honors chemistry courses and they will also prove useful to 1st year undergraduate students of chemistry.

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